y^2-3y-28/3y^2=21y=36

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Solution for y^2-3y-28/3y^2=21y=36 equation: 



y^2-3y-28/3y^2=21y=36

We move all terms to the left:

y^2-3y-28/3y^2-(21y)=0



Domain of the equation: 3y^2!=0

y^2!=0/3

y^2!=√0

y!=0

y∈R



We add all the numbers together, and all the variables

y^2-24y-28/3y^2=0

We multiply all the terms by the denominator


y^2*3y^2-24y*3y^2-28=0

Wy multiply elements

3y^4-72y^3-28=0

We do not support eypression: y^4

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